> Please help with System of Equations, interest problem?

Please help with System of Equations, interest problem?

Posted at: 2014-12-05 
Let X = amount invested at 6%. (4000 - X) is the amount invested at 9%

( .06 * X ) + ( .09 * (4000 - X) ) = 270

360 - .03X = 270

.03X = 90

X = 3000

3000 at 6% and 1000 at 9%

Check: (3000 * .06) + (1000 * .09) = 180 + 90 = 270

Jerry is correct, but I thought I'd show you a step that he omitted:

( .06 * X ) + ( .09 * (4000 - X) ) = 270

0.06x + 360 - 0.09x = 270
360 - 0.03x = 270

360 - 270 = 0.03x

90 = 0.03x

90 / 0.03 = x

x = 3000
thus (4,000 - x) = 1,000
Siri invests $4000 in 2 accounts, one at 6% interest, the other at 9% interest for 1 year. At the end of the year she had earned $270 in interest. How much did Siri invest in each account?

1. Label the variables in the problem.

2. Write the system of equations that models the problem.