5400 and 7200
Taking SI and assuming time period to be equal
x*6%*t= (12600-x)*8%*t
solve for x and you will get x=7200
$7200 should be invested in the 6% scheme while 5400 for the 8% one
where x = weight of investment returning 6%, thus (1 - x) = weight of investment returning 8%...
0.06x = 0.08(1 - x)
0.06x = 0.08 - 0.08x
0.14x = 0.08
x = 0.08 / 0.14
x = 0.57143
0.57143 * 12,600 = $7,200 invested at 6%
and (12,600 - 7200) = $5,400 invested at 8%
alternatively...(1 - x) = 0.42857, and 12,600 * 0.42857 = $5,400
How can $12600 be split between two investments, one at 6% annually and another at 8% annually, so that the interest on the two investments are the same.
